| ERFC2 | |
Normal cumulative distribution function.
Synopsis:
y=erfc2(x,m,v)
Description:
It computes normal cumulative distribution function
erfc2(x) = 1/sqrt(2*pi)*v) *
integral from x to inf of exp(-(t-m)^2/(2*v^2) dt
Input:
x [1x1] Real number.
m [1x1] Mean value.
v [1x1] Variance.
Output:
y [1x1] Error function.
See also
ERFC.
About: Statistical Pattern Recognition Toolbox
(C) 1999-2003, Written by Vojtech Franc and Vaclav Hlavac
Czech Technical University Prague
Faculty of Electrical Engineering
Center for Machine Perception
Modifications:
28-apr-2004, VF